1. Си / Говнокод #18435

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    void perestanovka(int a[13][13], int n, int m){
	 int maxim, minim, temp,i;
	
	 for (i=0; i<n; i++){
         minim=0;
	 	 for (int j=1; j<m; j++){
 	  	if(a[i][j]<a[i][minim]) minim=j;
   	  }
	 temp=a[i][0];
     a[i][0]=a[i][minim];
     a[i][minim]=temp;}
			 
 	  for (int j=0; i<n; i++){
	  	  maxim=0;
	 	 for (int j=1; j<m; j++){
		 	 if(a[i][j]>a[i][maxim]) maxim=j;
		 }
		 temp=a[i][m-1];
         a[i][m-1]=a[i][maxim];
	     a[i][maxim]=temp; }
 }

    Запостил: lanior, 04 Июля 2015

    Комментарии (6) RSS

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